학술논문
Simple Proofs for $\sum\limits^\infty_{k=1} \frac{1}{k^2} = \frac{\pi^2} {6}$ and sin $x = x \prod\limits^\infty_{k=1} \bigg(1 - \frac{x^2}{k^2\pi^2} \bigg)$
Document Type
research-article
Author
Source
Mathematics Magazine, 1996 Apr 01. 69(2), 122-125.
Subject
Language
English
ISSN
0025570X
19300980
19300980